«Правильно ли я понял, что Зеленский решил опробовать на работоспособность пятую статью устава НАТО?!» — задал риторический вопрос дипломат.
foo * (*bar[2]); // This is parsed as a declaration (and not an expression because of the first rule)As for anonymous function pointer arguments and the cast operator: I never use the former, and I’m still experimenting with the latter. My current plan is to add a simple check for the identifier in (foo)(bar). If foo is a single identifier, I’ll parse it as a type cast—since I never write (MyFunc)(arg). If foo is a subexpression or contains multiple identifiers, it gets trickier, because I can imagine writing something like (cond ? func1 : func2)(arg). In that case, it might be manageable to check whether the expression inside the parentheses is a type (or arithmetic) expression.
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В Иране издали фетву о джихаде с призывом пролить кровь Трампа20:58
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